Tr\u01b0\u1eddng h\u1ee3p th\u1ee9 1<\/strong> : S\u1ed1 B c\u00f3 2 s\u1ed1 cu\u1ed1i gi\u1ed1ng nhau. ch\u00fang ta s\u1ebd b\u1ecf c\u1ea7u n\u00e0y kh\u00f4ng n\u00ean \u0111\u00e1nh. \nVD<\/strong> th\u1ef1c t\u1ebf : Ng\u00e0y 3\/6\/2024 s\u1ed1 B l\u00e0 76855. Ch\u00fang ta th\u1ea5y 2 s\u1ed1 cu\u1ed1i c\u1ee7a B l\u00e0 55 n\u00ean s\u1ebd b\u1ecf c\u1ea7u n\u00e0y.<\/p>\n
Soi c\u1ea7u song th\u1ee7 l\u00f4 gh\u00e9p c\u1ea7u t\u00ecm s\u1ed1 \u0111\u1ec1 tr\u00fang<\/figcaption><\/figure>\n
Tr\u01b0\u1eddng h\u1ee3p th\u1ee9 2<\/strong> : s\u1ed1 th\u1ee9 2 v\u00e0 s\u1ed1 th\u1ee9 3 c\u1ee7a B kh\u00e1c nhau nh\u01b0ng m\u1ed9t trong hai s\u1ed1 \u0111\u00f3 tr\u00f9ng v\u1edbi s\u1ed1 th\u1ee9 2 c\u1ee7a A. Ch\u00fang ta s\u1ebd v\u1eadn d\u1ee5ng theo quy t\u1eafc \u1edf b\u01b0\u1edbc 3 nh\u01b0 b\u00ecnh th\u01b0\u1eddng v\u1edbi s\u1ed1 kh\u00e1c nhau c\u00f2n s\u1ed1 tr\u00f9ng nhau kh\u00f4ng so s\u00e1nh \u0111\u01b0\u1ee3c th\u00ec ta s\u1ebd theo nguy\u00ean t\u1eafc c\u1ee7a c\u1eb7p s\u1ed1 kh\u00e1c.<\/p>\n
Soi c\u1ea7u song th\u1ee7 l\u00f4 gh\u00e9p c\u1ea7u t\u00ecm s\u1ed1 \u0111\u1ec1 tr\u00fang<\/figcaption><\/figure>\n
VD<\/strong> : ng\u00e0y 15\/5\/2024 nh\u01b0 h\u00ecnh tr\u00ean ta c\u00f3 s\u1ed1 A l\u00e0 35952, s\u1ed1 B l\u00e0 89532. Ch\u00fang ta s\u1ebd t\u00ecm \u0111\u01b0\u1ee3c l\u00f4 53 v\u00e0 52. Khi \u0111\u00f3 so s\u00e1nh l\u1ed9n hay kh\u00f4ng l\u1ed9n ta c\u00f3 2 l\u00f4 59 v\u00e0 55. Ta n\u00ean x\u00e9t theo b\u01b0\u1edbc 3 do l\u00f4 55 kh\u00f4ng so s\u00e1nh \u0111\u01b0\u1ee3c n\u00ean ta theo quy t\u1eafc c\u1ee7a l\u00f4 59 (s\u1ed1 nh\u1ecf \u0111\u1ee9ng tr\u01b0\u1edbc s\u1ed1 l\u1edbn) n\u00ean l\u00f4 59 kh\u00f4ng l\u1ed9n l\u00f4 => 53 c\u0169ng kh\u00f4ng l\u1ed9n n\u00ean l\u00f4 52 c\u0169ng kh\u00f4ng l\u1ed9n.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p th\u1ee9 3<\/strong> : S\u1ed1 th\u1ee9 2 v\u00e0 s\u1ed1 th\u1ee9 3 c\u1ee7a B gi\u1ed1ng nhau v\u00e0 tr\u00f9ng v\u1edbi s\u1ed1 th\u1ee9 2 c\u1ee7a A. Ta s\u1ebd b\u1ecf c\u1ea7u n\u00e0y.<\/p>\n
VD<\/strong> : S\u1ed1 A l\u00e0 18674,s\u1ed1 B l\u00e0 68871. Ta th\u1ea5y s\u1ed1 th\u1ee9 2 v\u00e0 3 c\u1ee7a B tr\u00f9ng v\u1edbi s\u1ed1 th\u1ee9 2 c\u1ee7a A n\u00ean c\u1ea7u n\u00e0y ta b\u1ecf.<\/b><\/p>\n
B\u01b0\u1edbc 5: C\u1ea7u n\u00e0y b\u1ea1n n\u00ean theo bao nhi\u00eau ng\u00e0y<\/strong><\/h3>\n\n
Khi t\u00ecm \u0111\u01b0\u1ee3c song th\u1ee7 l\u00f4 Vip ch\u00fang ta s\u1ebd theo c\u1ea7u n\u00e0y 2 ng\u00e0y. N\u1ebfu 2 ng\u00e0y kh\u00f4ng v\u1ec1 ch\u00fang ta b\u1ecf lu\u00f4n. T\u00ednh c\u1ea7u kh\u00e1c \u0111\u1ec3 ch\u01a1i.<\/li>\n