{"id":18134,"date":"2024-04-07T04:38:59","date_gmt":"2024-04-07T04:38:59","guid":{"rendered":"https:\/\/soicau4041.minhngocxoso.com\/?p=18134"},"modified":"2024-04-07T04:38:59","modified_gmt":"2024-04-07T04:38:59","slug":"cach-bat-tong-dac-biet-chuan-xac-nhat-tu-cac-cao-thu","status":"publish","type":"post","link":"https:\/\/soicauveso.com\/cach-bat-tong-dac-biet-chuan-xac-nhat-tu-cac-cao-thu\/","title":{"rendered":"c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t chu\u1ea9n x\u00e1c nh\u1ea5t t\u1eeb c\u00e1c cao th\u1ee7"},"content":{"rendered":"
<\/p>\n\n\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00f4 \u0111\u1ec1 l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p \u0111\u01a1n gi\u1ea3n, d\u1ec5 hi\u1ec3u, d\u00f9 l\u00e0 ng\u01b0\u1eddi m\u1edbi v\u1eabn c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng. H\u01a1n n\u1eefa, t\u00ednh hi\u1ec7u qu\u1ea3 c\u1ee7a ph\u01b0\u01a1ng ph\u00e1p \u0111\u01b0\u1ee3c \u0111\u00e1nh gi\u00e1 kh\u00e1 l\u00e0 cao. \u0110\u1ec3 t\u00ecm hi\u1ec3u r\u00f5 h\u01a1n v\u1ec1 c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1, h\u00e3y xem ngay b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y c\u1ee7a ch\u00fang t\u00f4i nh\u00e9!!!<\/p>\n\n\n\n
T\u1ed5ng \u0111\u1ec1 ch\u00ednh l\u00e0 t\u1ed5ng c\u1ee7a 2 s\u1ed1 cu\u1ed1i trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t, d\u00f9 l\u00e0 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc, mi\u1ec1n Nam hay l\u00e0 mi\u1ec1n Trung th\u00ec kh\u00e1i ni\u1ec7m n\u00e0y v\u1eabn c\u00f3 c\u00f4ng th\u1ee9c t\u00ednh chung nh\u01b0 v\u1eady. N\u1ebfu tr\u01b0\u1eddng h\u1ee3p t\u1ed5ng \u0110B c\u1ee7a 2 k\u1ef3 quay th\u01b0\u1edfng li\u00ean t\u1ee5c tr\u00f9ng nhau th\u00ec s\u1ebd g\u1ecdi l\u00e0 b\u1ec7t t\u1ed5ng.<\/p>\n\n\n\n
Soi c\u1ea7u \u0111\u1eb7c bi\u1ec7t theo t\u1ed5ng c\u00f3 ngh\u0129a l\u00e0 c\u00e1ch soi l\u00f4 \u0111\u1ec1 ng\u00e0y h\u00f4m sau d\u1ef1a v\u00e0o t\u1ed5ng c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y h\u00f4m tr\u01b0\u1edbc.<\/p>\n\n\n\n
Ng\u01b0\u1eddi ta c\u00f2n ph\u00e2n chia t\u1ed5ng \u0111\u1ec1 th\u00e0nh nhi\u1ec1u d\u1ea1ng: t\u1ed5ng ch\u1eb5n (0, 2, 4, 6, 8), t\u1ed5ng l\u1ebb (1, 3, 5, 7, 9) v\u00e0 m\u1ed9t s\u1ed1 lo\u1ea1i kh\u00e1c n\u1eefa l\u00e0 t\u1ed5ng l\u1edbn h\u01a1n 5 v\u00e0 b\u00e9 h\u01a1n 5.<\/p>\n\n\n\n
V\u00ed d\u1ee5 nh\u01b0 sau, gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 57353 th\u00ec c\u00f4ng th\u1ee9c t\u00ednh t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 5 + 3 = 8.<\/p>\n\n\n\n
\u0110\u00e2y l\u00e0 m\u1ed9t trong nh\u1eefng c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 \u0111\u01a1n gi\u1ea3n, d\u1ec5 th\u1ef1c hi\u1ec7n nh\u01b0ng kh\u00f4ng k\u00e9m ph\u1ea7n hi\u1ec7u qu\u1ea3. \u0110\u1ed1i v\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng s\u1ed1 th\u1ee9 2 c\u1ee7a gi\u1ea3i 7 ng\u00e0y h\u00f4m tr\u01b0\u1edbc \u0111\u1ec3 l\u00e0m t\u1ed5ng \u0111\u1ec1 nu\u00f4i khung l\u00f4 3 \u2013 5 ng\u00e0y.<\/p>\n\n\n\n
V\u00ed d\u1ee5 ng\u00e0y 19\/1 con s\u1ed1 th\u1ee9 2 c\u1ee7a gi\u1ea3i 7 l\u00e0 78, t\u1ed5ng s\u1ebd l\u00e0 7 + 8 = 15. Nh\u01b0 v\u1eady, ta s\u1ebd d\u00f9ng t\u1ed5ng 5 \u0111\u1ec3 nu\u00f4i khung d\u00e0n \u0111\u1ec1 05 \u2013 50 \u2013 14 \u2013 41 \u2013 23 \u2013 32 \u2013 69 \u2013 96 \u2013 78 \u2013 87 trong 3 \u2013 5 ng\u00e0y ti\u1ebfp theo.<\/p>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p b\u1ea1c nh\u1edb l\u00f4 \u0111\u1ec1 m\u1eb7c d\u00f9 \u0111\u00e3 c\u00f3 t\u1eeb r\u1ea5t l\u00e2u, th\u1ebf nh\u01b0ng hi\u1ec7n nay v\u1eabn r\u1ea5t chu\u1ea9n x\u00e1c. Ch\u00fang l\u1eb7p \u0111i l\u1eb7p l\u1ea1i theo chu k\u1ef3 n\u00ean vi\u1ec7c v\u1eadn d\u1ee5ng s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i thu \u0111\u01b0\u1ee3c hi\u1ec7u qu\u1ea3 l\u1edbn.<\/p>\n\n\n\n
B\u1ea1n c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng m\u1ed9t s\u1ed1 nguy\u00ean t\u1eafc d\u01b0\u1edbi \u0111\u00e2y<\/p>\n\n\n\n
+ Th\u1ee9 2 t\u1ed5ng \u0111\u1eb7c bi\u1ec7t 2, 8 th\u01b0\u1eddng s\u1ebd n\u1ed5<\/p>\n\n\n\n
+ Th\u1ee9 3 hay ra t\u1ed5ng \u0111\u1ec1 1, 7<\/p>\n\n\n\n
+ Th\u1ee9 4 b\u1ea1n n\u00ean \u0111\u1ea7u t\u01b0 v\u00e0o t\u1ed5ng 0, 9<\/p>\n\n\n\n
+ Th\u1ee9 t\u1ed5ng 2, 6 s\u1ebd th\u01b0\u1eddng xu\u1ea5t hi\u1ec7n<\/p>\n\n\n\n
+ Th\u1ee9 6 hay ra t\u1ed5ng \u0111\u1eb7c bi\u1ec7t 3, 4<\/p>\n\n\n\n
+ Th\u1ee9 7 t\u1ed5ng 7, 1 s\u1ebd ra nhi\u1ec1u nh\u1ea5t<\/p>\n\n\n\n
+ Ch\u1ee7 Nh\u1eadt t\u1ed5ng l\u00f4 \u0111\u1ec1 5, 8 ch\u1eafc ch\u1eafn s\u1ebd n\u1ed5.<\/p>\n\n\n\n B\u1ea1n h\u00e3y d\u00f9ng s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a gi\u1ea3i \u0111\u1ec1 h\u00f4m th\u1ee9 2 \u0111\u1ec3 l\u00e0m t\u1ed5ng chu\u1ea9n, l\u1eadp d\u00e0n \u0111\u1ec1 c\u1ee7a t\u1ed5ng n\u00e0y \u0111\u1ec3 nu\u00f4i l\u00f4 trong 7 ng\u00e0y, t\u1ef7 l\u1ec7 th\u1eafng l\u00e0 t\u01b0\u01a1ng \u0111\u1ed1i cao.<\/p>\n\n\n\n V\u00ed d\u1ee5, th\u1ee9 2 ng\u00e0y 17\/7 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 05488, b\u1ea1n h\u00e3y l\u1ea5y 0 l\u00e0m t\u1ed5ng chu\u1ea9n. Ch\u00fang ta c\u00f3 d\u00e0n sau nh\u01b0 sau 00, 191, 282, 373, 464, 55.<\/p>\n\n\n\n K\u1ebft qu\u1ea3<\/p>\n\n\n\n Ng\u00e0y 18\/7 l\u00f4 55, 82, 91, 19 \u0111\u00e3 xu\u1ea5t hi\u1ec7n<\/p>\n\n\n\n Ng\u00e0y 19\/7 n\u1ed5 con l\u00f4 55, 82, gi\u1ea3i \u0110B xu\u1ea5t hi\u1ec7n con 37<\/p>\n\n\n\n Ng\u00e0y 20\/7 v\u1ec1 con l\u00f4 19, 37, 55, 82, 91<\/p>\n\n\n\n Ng\u00e0y 21\/7 con l\u00f4 19, 55, 28, 91 \u0111\u00e3 ra v\u00e0 gi\u1ea3i \u0110B c\u0169ng v\u1ec1 con 64.<\/p>\n\n\n\n Ng\u00e0y 22\/7 xu\u1ea5t hi\u1ec7n l\u00f4 91<\/p>\n\n\n\n Ng\u00e0y 23\/7 l\u00f4 28, 55 ra<\/p>\n\n\n\n B\u1eaft t\u1ed5ng \u0111\u1ec1 d\u1ef1a v\u00e0o quy lu\u1eadt Pascal, b\u1ea1n ch\u1ec9 c\u1ea7n d\u00f9ng 5 con s\u1ed1 gi\u1ea3i \u0111b v\u00e0 5 s\u1ed1 gi\u1ea3i nh\u1ea5t gh\u00e9p l\u1ea1i v\u1edbi nhau. Ti\u1ebfp theo \u0111\u00f3, h\u00e3y c\u1ed9ng ch\u00fang l\u1ea1i theo lu\u1eadt c\u1ed9ng Pascal: c\u1ed9ng 2 s\u1ed1 li\u1ec1n k\u1ec1 nhau li\u00ean ti\u1ebfp, \u0111\u1ebfn khi ch\u1ec9 c\u00f2n l\u1ea1i 2 s\u1ed1 d\u00f9ng \u0111\u1ec3 \u0111\u00e1nh \u0111\u00e1nh l\u00f4 h\u00f4m sau.<\/p>\n\n\n\n Trong tr\u01b0\u1eddng h\u1ee3p t\u1ed5ng l\u1edbn h\u01a1n 10, th\u00ec ta s\u1ebd ch\u1ec9 l\u1ea5y b\u1ed9 s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb v\u00e0 c\u1ea7u n\u00e0y n\u00ean nu\u00f4i trong 3 ng\u00e0y.<\/p>\n\n\n\n \u0110\u1ec3 hi\u1ec3u r\u00f5 h\u01a1n b\u1ea1n h\u00e3y xem ngay v\u00ed d\u1ee5 d\u01b0\u1edbi \u0111\u00e2y ( \u0110\u1ec3 nh\u00ecn t\u1ed5ng quan nh\u1ea5t b\u1ea1n c\u00f3 th\u1ec3 xem b\u1ea3ng \u0111\u1eb7c bi\u1ec7t tu\u1ea7n nh\u00e9 ch\u1ec9 c\u00f3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t hi\u1ec7n l\u00ean b\u1ea3ng) <\/p>\n\n\n\n Ng\u00e0y 21\/7, gi\u1ea3i \u0111b v\u1ec1 20464, gi\u1ea3i nh\u1ea5t v\u1ec1 10454, gh\u00e9p c\u00e1c s\u1ed1 l\u1ea1i ch\u00fang ta \u0111\u01b0\u1ee3c 2046410454. T\u1eeb \u0111\u00f3, c\u1ed9ng theo Pascal ta \u0111\u01b0\u1ee3c<\/p>\n\n\n\n 2046410454 -> 240051499 -> 64056538 -> 0451181 -> 496299 -> 35818 -> 8399 -> 128 -> 30.<\/p>\n\n\n\n \u0110\u1ec3 bi\u1ebft t\u1ed5ng \u0111\u1ec1 gan b\u1ea1n h\u00e3y d\u1ef1a v\u00e0o b\u1ea3ng KQXS \u0111\u00e3 n\u1ed5, n\u1ebfu trong 1 tu\u1ea7n t\u1ed5ng n\u00e0o ch\u01b0a xu\u1ea5t hi\u1ec7n th\u00ec h\u00e3y t\u1eadp trung v\u00e0o t\u1ed5ng \u0111\u00f3. Ph\u01b0\u01a1ng ph\u00e1p b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t n\u00e0y n\u1ebfu k\u1ebft h\u1ee3p v\u1edbi ch\u1ea1m nu\u00f4i tu\u1ea7n th\u00ec t\u1ef7 l\u1ec7 th\u1eafng s\u1ebd l\u00ean t\u1edbi 80% \u0111\u1ea5y nh\u00e9!!!<\/p>\n\n\n\n Tr\u00ean \u0111\u00e2y ch\u00fang t\u00f4i \u0111\u00e3 b\u1eadt m\u00ed cho b\u1ea1n nh\u1eefng c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t chu\u1ea9n x\u00e1c nh\u1ea5t \u0111\u01b0\u1ee3c \u0111\u00fac k\u1ebft t\u1eeb kinh nghi\u1ec7m c\u1ee7a c\u00e1c cao th\u1ee7. H\u00e3y l\u1ef1a ch\u1ecdn cho m\u00ecnh ph\u01b0\u01a1ng ph\u00e1p ph\u00f9 h\u1ee3p nh\u1ea5t v\u1edbi ngu\u1ed3n v\u1ed1n \u0111\u1ec3 mang l\u1ea1i kho\u1ea3n l\u1ee3i nhu\u1eadn kh\u1ee7ng, \u0111\u1ea7y h\u1ea5p d\u1eabn. Ch\u00fac c\u00e1c b\u1ea1n th\u00e0nh c\u00f4ng<\/p>\n\n\n <\/p>\r\n\r\nB\u1eaft t\u1ed5ng \u0111\u1ec1 th\u00f4ng qua s\u1ed1 \u0111\u1ea7u ti\u00ean gi\u1ea3i \u0111\u1eb7c bi\u1ec7t th\u1ee9 2<\/h2>\n\n\n\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t b\u1eb1ng quy lu\u1eadt Pascal<\/h3>\n\n\n\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t theo t\u1ed5ng \u0111\u1ec1 l\u00f4<\/h3>\n\n\n\n
k\u1ebft qu\u1ea3 v\u00e0ng mi\u1ec1n b\u1eafc<\/span><\/h3>\r\n